Question

Derive an expression for the potential energy of a system of two point charges in an external field.​

Answer 1

Explanation:

Coulombic force acting on a test charge F=r2kQq where k=4πϵo1

Potential energy of the two charges U=−∫F.dr

∴ U=−∫r2kQqdr

Or U=−kQq∫r21dr

Or U=−kQq×r−1

⟹ U=rkQq

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