Question

Derive an expression for the potential energy of an objective​

Answer 1

Answer:

Derivation for the equation of Potenstial Energy: Let the work done on the object against gravity = W Work done, W = force × displacement Work done, W = mg × h Work done, W = mghSince workdone on the object is equal to mgh, an energy equal to mgh units is gained by the object

Explanation:

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Answer 2

Answer:hey mate. here is your answer

Since workdone on the object is equal to mgh, an energy equal to mgh units is gained by the object . This is the potential energy (Ep) of the object. It is clear that the work done is equal to the change in the kinetic energy of an object. If u = 0, the work done will be W =12mv2 W = 1 2 m v 2 .

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Explanation: