Question

Derive an expression for the potential energy of an elastic stretched spring.​

Answer 1

Answer:

Hooke's Law, F = -kx, where F is the force and x is the elongation. The energy stored can be found from integrating by substituting for force, and we find, The energy stored = kx2/2, where x is the final elongation.

Explanation:

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Answer 2

Answer:-

Hooke's Law, F = -kx, where F is the force and x is the elongation. The energy stored can be found from integrating by substituting for force, and we find, The energy stored = kx2/2, where x is the final elongation.

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