Question

derive an expression for the rate constant of second order reaction when the initial concentration are the same​

Answer 1

boxed { A + B longrightarrow Product } Case 1: When concentration of reactants are equal If a is the initial concentration of reactants A and B, and x amount of A and B are reacted at time t, so at time t the concentrations will be, underset { left( a - x right) }{ A } + underset { left( a - x right) }{ B } .

Hope it helps you.

Answer 2

Answer:

Same concenetration

rate = k [A]2

Different concentrations:

rate = k [A] [B]

Now, assuming that these were NOT the answers you were seeking, the integrated rate laws for each condition are:

Same concentrations:

1[Af]−1[Ai]=kΔt

Different concentrations:

1([Bi]−[Ai])ln[Ai][Bf][Bi][Af]=kΔt

Explanation: