Question

Derive an expression for the rate constant of zero order reaction

Answer 1

Hi mate.

Thanks for asking this question,

Here is your answer,


$zero \: order \: reaction$

The rate in which rate of chemical

reaction is independent upon active

concentration of reactant called as Zero

Order Reactions.

e. g)

H2 + Cl2 > 2Hcl

$rate \: = k ({h2})^{o} \: ( {cl2})^{o}$


$differential \: equation$


Please take a help from the images .





BE BRAINLY !!!!!!!!!!!!!!!

Answer 2

Explanation :

Zero order reaction : A reaction is said to be of zero order if the rate is independent of the concentration of the reactants, that means the rate is directly proportional to the zeroth power of the concentration of the reactants.

For the reaction

$A\rightarrow \text{Products}$

If the reaction is zero order, then

$Rate=-\frac{d[A]}{dt}=k[A]^0=k$

or,

$d[A]=-kdt$

where, k is the rate constant.

Now integrating both sides, we get

$[A]=-kt+C$           .....(1)

where, C is the constant of integration

At t = 0, the concentration of the reactant $A=[A]_o$, where $[A]_o$ is the initial concentration of the reactant.

Therefore, $[A]_o=C$

Now substituting the value of 'C' in the equation (1), we get

$[A]=-kt+[A]_o$

$k=\frac{1}{t}\times ([A]_o-[A])$

This is the expression for the rate constant of zero order reaction.