Physics, asked by Priyanca, 11 months ago

Derive an expression for the ratio of de-Broglie wavelength associated with the electron orbiting in 2nd and 3rd excited states of H-atom..

Answers

Answered by Anonymous

$<body bgcolor = "r"> <font color =White>$

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

Second excited state (n=3)

Third excited state (n=4)

E=hcλ13.6n2=hcλ13.6n2hc=1λ λ= n2hc13.6

Now,

λ2λ3= n22hc13.6×13.6n32hcλ2λ3=n22n23=(3)2(4)2λ2λ3=916

$<marquee>ᴍʀ ꜱʜᴀʀᴇᴇꜰ(｡❤‿❤｡)</marqure>$

Previous Question

Next Question

Similar questions

Political Science, 5 months ago

Physics, 5 months ago

Social Sciences, 5 months ago

Business Studies, 11 months ago

English, 11 months ago

Science, 1 year ago

Math, 1 year ago

Physics, 1 year ago