Question

derive an expression for the rotational kinetic energy and rotating with angular velocity Omega

Answer 1

Hola User_________________

Here is Your Answer...!!!
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⭐Actually welcome to the concept of the ROTATIONAL DYNAMICS...

⭐Basically here we know that ....

⭐K.E.= 1/2 mv^2

⭐but since body is in rotation but not in translational motion ...

⭐therefore we have to apply .. v= w×r ( ..here 'w'= Angular velocity (omega) )


⭐so we get the derived formula as

⭐Rotational K.E. = 1/2 I w^2

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Hope it helps u....☺

Answer 2

HEY MATE HERE IS YOUR ANSWER

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Rotational Kinetic Energy
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We know that

$k.e = \frac{1}{2} m {v}^{2}$


Since, v = rw

Therefore,

R. K. E = 1/2 m(rw) ^2

$= > \frac{1}{2} m {r}^{2} {w}^{2}$
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Hope it will help you