Question

derive an expression for time period of simple pendulum?

Answer 1

a=omega square * x. (negative sign shows direction therefore omitting it . ) 
=> omega =√a/√x. ....(1) 
= T =2pie/omega 
=>omega = 2π/T (2) 
equating 2 and 1 
2π/T= √a/√x 
=> T = 2π√x/√a

Answer 2

$\textbf{Answer is in Attachment !!}$