Derive an expression for time period of simple pendulum which may depend upon the mass of bob length of pendupum and acceleration due to gravity
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T directly proportional to m l g. T= K mlg
m^x l^y. g^z
M^x L^y (LT^-2)^z
x=0
y=1/2
z=-1/2
K=2π
T=2π√l/g
m^x l^y. g^z
M^x L^y (LT^-2)^z
x=0
y=1/2
z=-1/2
K=2π
T=2π√l/g
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