derive an expression for torque acting on a rectangular current carrying loop kept in a uniform magnetic fieldB. indicate the direction of torque acting on the loop.
Answers
Answer:
Explanation:
Consider a rectangular coil PQRS suspended in a uniform magnetic field →
B, with its Axis perpendicular to the field
Figure (a) a rectangular loop PQRS in a
→
uniform magnetic field B
(b) top view of the loop magnetic dipole moment m is shown.
Let I = current flowing through the coil PQRS
a,b =sites of the coil PQRS
A= ab = area of the coil
According to the Fleming's left hand rule the magnetic forces on side PS and q are equal opposite and collinear (along the axis of the loop) so there resultant is zero.
The sides PQ experiences a normal in word forces equal to the IbB
while the sides Rs experiences and equal normal outward force. These two forces former couple which exerts a Torque you given by
T= force *perpendicular distance
If the rectangular loop has N turns the torque increases N times
The direction of the Torque is such that it rotates the loop clockwise about the axis of suspension
Answer:
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Explanation:
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