Question

Derive
an expression for value of g at
height h?​

Answer 1

For acceleration due to gravity, at height h we have g'=g (1-2h/R), but when h=R/2, then g'=0, and if 2h>R, then g'=-ve.

Answer 2

Answer:

Explanation:let we consider,

radius of earth R and mass is M

and we know that acceleration due to gravity at surface

g= GM/R^2. ---- (i)

G is universal gravitational constant.

consider, a mass m is at above the earth at height h and g ′ is acceleration due to gravity at height h.

Therefore,

g'=GM/(R+h)^2. ----- (ii)

divide, (ii) by (i)

g′/g= R^2/(R+h)^2

g'=gR^2/(R+h)^2

Or h<<<R,

=g(1− 2h/R)

Brainlist me if you get this