Physics, asked by KasankarRushikesh, 3 months ago

Derive an expression for velocity in SHM

Answers

Answered by Vamsirishi
1

Answer:

the expressions for velocity and acceleration of a particle executing simple harmonic motion are v=ω√A2−x2and a=−ω2x respectively.

Explanation:

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Answered by Anonymous
10

Answer:

The velocity of the mass on a spring, oscillating in SHM, can be found by taking the derivative of the position equation: v(t)=dxt

=ddt(Acos(ωt+φ))

=−Aωsin(ωt+ϕ

)=−vmaxsin(ωt+φ)

The maximum velocity occurs at the equilibrium position (x=0) when the mass is moving toward x=+A .


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