Question

Derive an expression for velocity of cyclist on a banked road and explain bending
of cyclist.

Answer 1

Answer:

Mass of cyclist + cycle =M

radius of curvature of the curved path =R

ANgle of inclination from vertical=θ

acceleration due to gravity=g

velocity of cyclist =v

Let the normal force : N from the ground on to cyclist. Balance forces in horizontal and vertical directions.

Nsinθ=

R

Mv

2

= centripetal force for the cyclist to move in a curve of radius R

Ncosθ=Mg = weight balanced by normal reaction from ground

SO divide equ 1 by equ 2

tanθ=

Rg

v

2

Compairing with the equation

tanθ=

Rg

v

n

as given in question

Required answer is n=2