Question

Derive an expression for velocity of elastic collision in one dimension.​

Answer 1

Answer:

m1 and m2 moving with velocities u1 and u2 along the same straight line. 

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collision

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision 

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision p1=m1u1+m2u2

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision p1=m1u1+m2u2Kinetic energy of mass  m1=21m1u12

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision p1=m1u1+m2u2Kinetic energy of mass  m1=21m1u12Kinetic energy of mass  m2=21m2u22

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision p1=m1u1+m2u2Kinetic energy of mass  m1=21m1u12Kinetic energy of mass  m2=21m2u22Thus,

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision p1=m1u1+m2u2Kinetic energy of mass  m1=21m1u12Kinetic energy of mass  m2=21m2u22Thus,Total kinetic energy before collision is

m1 and m2 moving with velocities u1 and u2 along the same straight line. And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.Before collisionMomentum of mass  m1=m1u1Momentum of mass  m2=m2u2Total momentum before collision p1=m1u1+m2u2Kinetic energy of mass  m1=21m1u12Kinetic energy of mass  m2=21m2u22Thus,Total kinetic energy before collision isK.E=21m1u12