Physics, asked by beastmaster65, 1 year ago

derive an expression for work done during and adiabatic process

Answers

Answered by abhi178
17
process of workdone in adiabatic process ======

we know ,
W=PdV
also PV^Y=constant (K)
P =K/V^Y
W=K/V^Y.dV
integrate .

W =K[V^(1-Y)/(1-Y)]
put K =PV^Y

then ,
W =[PV/(1-Y)]
now put limit P2V2 and P1V1

now,
W =(P2V2-P1V1)/(1-Y)
this is expression of workdone where P2 ,V2 , P1 , V1 are final pressure , volume , initial pressure , volume respectively .
and Y is atomicity (gamma )


abhi178: now look answer
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