Question

derive an expression for work done in adiabatic process.​

Answer 1

Answer:

Adiabatic process :    PVγ=K

So,     P=KV−γ

Work done    W=∫PdV

Or     W=∫KV−γdV

Or     W=K×1−γV−γ+1∣∣∣∣∣V1V2

Or     W=1−γK×[V2−γ+1−V1−γ+1]

Or     W=1−γ1×[KV2−γ+1−KV1−γ+1]

Or     W=1−γ1×[P2V2γV2−γ+1−P1V1γV1−γ+1]

Or     W=1−γ