Derive an expression K.E = ½ mv^2 for a freely falling body of mass m
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Answers
Answer:
Kinetic Energy:
The energy possessed by an object due to its motion is called as kinetic energy.
Derivation:
Let us consider an object of mass "m" which is at rest on smooth horizontal plane.
Let a Force ,F acts on the object and let the object from rest moves from point A to point B and covers a displacement S.
The Work done by Force on the object is :
Workdone = Force x displacement.
W=F×S ____(1).
From third equation of motion;
V
2
−U
2
=2aS
S=
2a
V
2
−U
2
______(2)
By Newtons second law of motion:
F=ma
From equation 1 and 2
W=
2a
m∗a∗(V
2
−U
2
)
As we have assumed object is at rest, U=0
W=
2
mV
2
The Work Done appears as kinetic energy of the body.
Therefore,
K.E=(
2
1
)mV
2
Kinetic Energy:
The energy possessed by an object due to its motion is called as kinetic Energy.
Derivation:
Let us consider an object of mass " m " which is at rest on smooth horizontal plane.
Let a Force , F acts on the object and let the object from rest moves from point A to point B and covers a displacement S.
The WORK Done by Force on the object is :
Workdone = Force x displacement.
W= FxS ____(1).
From third equation of motion;
V^2 -U^2 =2aS
S= V^2 -U^2/2a ______(2)
By Newtons second law of motion:
F= ma
From equation 1 and 2
W= m*a* (V^2- U^2)/2a
As we have assumed object is at rest, u=0
W=m*V^2/2
The WORK Done appears as kinetic energy of the body.
Therefore,
K.E = (1/2 )mv^2