Chemistry, asked by Chhottenn, 1 month ago

Derive an expression relating Van't hoff factor (i),degree of dissociation and number of ions produced by an electrolyte when it undergoes dissociation in nature​

Answers

Answered by sarasukm15
0

Explanation:

For weak electrolytes, van't Hoff factor 'i' is a measure of the degree of dissociation of weak electrolyte.

Higher is the value of the van't Hoff factor, higher will be the degree of dissociation.

The relationship between the van't Hoff factor i and the degree of dissociation α is

α=

n−1

i−1

Here n is the number of ions produced by the complete dissociation of 1 mole of substance

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