Physics, asked by chavanroshan524, 10 months ago

derive an expression that reletes agular momentum with the angular velocity of a rigin body

Answers

Answered by AgniDevan

0

Answer:

L=I×omega

Explanation:

L is the angular momentum

I is the moment of inertia

Omega is the angular velocity.

as we know, L=mv×r

L=mv×r(r/r) multiply num. and den. by r

rearranging the terms...

L=(mr^2)(v/r)

L=I×omega

Hope it's clear...

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