Derive and express to find the equivalent resistance of two resistor connected in series
please answer me
Answers
Answered by
0
Answer:
the equivalent resistance connected in series is the sum of individual resistor.
Explanation:
R= r1+r2.................+rn
Answered by
7
Answer:
In series,
R(eq) = R1 + R2 .
In parallel,
R(eq) = 1/R1 + 1/R2 .
Thanks..
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