Derive and expression for the equivalent resistance of three resistors r1r2r3 connected in series
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Heya......!!!
_________________
Three Resistors are connected in Series .
Let the resistors be - R1 , R2 and R3 .
Since the 3 resistors are connected in series then the current ( i ) through each of them will be same .
So ,, By ohm's law the potential diffrence across each resistor is
:- V1 = iR1
V2 = iR2
V3 = iR3
and total potential = V
that is V = V1 + V2 + V3
putting values of V1 , V2 and V3 , we get ,
»» V = i×R1 + i×R2 + i×R3
and Let equivalent Resistance be ( Re )
by Ohm's law :-- V =i×Re
-- Therefore
➡ i×Re = iR1 + iR2 + iR3
taking ( i ) common
♦ Re = R1 + R2 + R3 ♦
We can say that in series combination , the equivalent resistance is the sum of individual sum of resistance .
========================
Hope It helps You ☺
_________________
Three Resistors are connected in Series .
Let the resistors be - R1 , R2 and R3 .
Since the 3 resistors are connected in series then the current ( i ) through each of them will be same .
So ,, By ohm's law the potential diffrence across each resistor is
:- V1 = iR1
V2 = iR2
V3 = iR3
and total potential = V
that is V = V1 + V2 + V3
putting values of V1 , V2 and V3 , we get ,
»» V = i×R1 + i×R2 + i×R3
and Let equivalent Resistance be ( Re )
by Ohm's law :-- V =i×Re
-- Therefore
➡ i×Re = iR1 + iR2 + iR3
taking ( i ) common
♦ Re = R1 + R2 + R3 ♦
We can say that in series combination , the equivalent resistance is the sum of individual sum of resistance .
========================
Hope It helps You ☺
john44:
please answer my question
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