Question

derive any equation for average speed for vertically projected body from point of projection to highest point​

Answer 1

Answer:

u/2

Explanation:

Average speed = Total Displacement / Total Time taken

So, when the object is launched:

u = u, a = -g, v = 0

v = u + at :   0 = u - gt :   t = u/g

$v^{2} - u^2 = 2as$

- $u^2$ = 2(-g)s :              s = $u^2$ /2g

Avg. Speed:  $u^2$ /2g / u/g :  ($u^2$ * g) /(2g * u) : u/2

Hence u/2 is the average speed.

Hope it helps!