Question

Derive any two equations of motion graphically.​

Answer 1

1. Consider an object is moving with a uniform acceleration “a” along a straight line.
2. The initial and final velocities of the object at time t = 0 and t = t are u and v respectively.
3. Draw another line BA from point B parallel to Y-axis which meets at E at y-axis.

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Answer 2

Answer:

Derivation of Third Equation of Motion by Graphical Method

1) S = ½ (Sum of Parallel Sides) × Height.

2) S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...

3)S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...

4)S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.

5)S= ½ (v+u) × (v-u)/a.

6) S = (v2-u2)/2a.