.
Derive:
b. v2 = u2 + 2as
a. s = ut + 1
ut + 2 at 2
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Explanation:
We know
(i) a = dv/dt
dv = adt
Intergrating
∫ dv = ∫ adt
V at k = + − − − −(1)
Where K is constant of integration
when t = 0 v = u
⇒ K = u
⇒ V = at + u
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