Question

derive by calculus method
$v 2 = u2 + 2as$

Answer 1

a=dv/dt

a =dv/dx * dx/dt (using chain rule)

since dx/dt=v

a= v dv/dx

a dx=v dv

a[dx]os =[v dv]uv

as=[v 1+1/2]uv

as=[v2/2]uv

as=v2-u2/2

therefore,

2as= v2-u2