Derive by the method of dimensions, an expression for the volume of a liquid flowing out
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of the pipe (iii) the pressure
gradient (p/l) along the pipe.
Answers
Answer:
method of dimensions, an expression for the volume of a liquid flowing out
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of the pipe (iii) the pressure
gradient (p/l) along
expression for the volume of a liquid flowing out
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of the pipe (iii) the pressure
gradient (p/l) along
Explanation:
method of dimensions, an expression for the volume of a liquid flowing out
method of dimensions, an expression for the volume of a liquid flowing out
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of the pipe (iii) the pressure
gradient (p/l) along
expression for the volume of a liquid flowing out
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of the pipe (iii) the pressure
gradient (p/l) along
expression for the volume of a liquid flowing out
per second (V) through a narrow pipe. Assume that rate of flow of the liquid depends on
(i) the coefficient of viscosity ‘η’ of the liquid (ii) the radius ‘r’ of
rupee = 100 paise. 10 ruppee = 1000 paise. 95/1000×100