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Derive cauchy riemann equation in polar form

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Answered by divya33331
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Answered by Harshitm077
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Answer:

Let f(z) = m(x,y) +iv(x,y), be a function on an open domain with continuous partial derivatives in the underlying real variables.

Then if , f is differentiable at z = x + i y , and only if

£u/£x(x,y) = £ v/£y (x,y) and = £ u/£y (x,y)  

= - £ v/- £ x (x,y).

So we have f ’ (z) = £u/£x(z) + I £u/£x(z)

Let f(z) = f(reiƟ)= u(r, Ɵ) +iv(r, Ɵ), be a function on an open domain that doesn't contain zero along with continuous partial derivatives in the underlying real variables.

Then if f is differentiable at z = reiƟ and only if r = r £u/£r = £v/£Ɵ

= £u /£Ɵ= -r£v/£r

Explanation:

Cauchy-Riemann Equations: D'Alembret Euler condition, also known as the Cauchy Riemann equation, is employed to evaluate the differentiability of a complex function. It is further utilized to verify the overall analyticity of the specified function and Its purpose is to determine a function's harmonic conjugates.

  • This equation is named after Augustin Cauchy (civil engineer and mathematics by profession) and Bernhard Riemann when it was found in 1851 after getting this idea while doing his survey for the dam.

For more information about cauchy-riemann equations - math.fandom.com/wiki/Cauchy%E2%80%93Riemann_conditions

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