Question

Derive distance covered by body during nth second of motion .​

Answer 1

Answer:

The distance travelled by a body in the nth second is given by the expression (2 + 3n). Find the initial velocity and acceleration. Also, find its velocity at the end of 2 seconds. - Hint:- We had to only compare the given distance with the formula to find the distance travelled in nth second i.e. d=u+a(n−12).

IS THIS HELPFUL?

Answer 2

Answer:

consider a particle moving with uniform  acceleration 'a' let u initial velocity of the particle

   distance  travelled during nth second=distance travelled nth second -distance travelled in [n-1] seconds

sn=un+1/2an2-{u[n-1]+1/2a[n-1]2}

un+1/2an2-{un-u+12a[n2-2n+1]}

un+1/2an2-un+u-1/2an2+an-1/2a

u+an-1/2a

sn=u+a[n-1/2]

i hope this may help you friend