Science, asked by nimki87, 1 year ago

Derive each and every Equation of motion for class 9th ​

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Answered by Rememberful
26

\textbf{Answer is in Attachment !}

Attachments:

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Answered by Anonymous
74
\huge\underline{\bold{\red{Answer\::}}}

\underline{\bold{1st\:equation\:of\:motion\::}}

a = uniform acceleration

s = distance travelled

u = initial velocity

v = final velocity

t = time

Acceleration = \dfrac{Change\:in\:velocity}{Time\:taken}

= \dfrac{BD}{OA} = \dfrac{AD\:-\:AB}{OA}

a = \dfrac{v\:-\:u}{t}

at = v - u

\boxed{\boxed{v\: =\: u\: + \:at}}

\underline{\bold{2nd\:equation\:of\:motion\::}}

s = OA × AB + \dfrac{1}{2} × CB × BD

s = t × u + \dfrac{1}{2} × t × at

\boxed{\boxed{s\:=\:ut\:+\:{\dfrac{1}{2}\:a{t}^{2}}}}

\underline{\bold{3rd\:equation\:of\:motion\::}}

s = \dfrac{1}{2} (OC + AD) (OA)

s = \dfrac{1}{2} (u + v) × \dfrac{v\:-\:u}{a}

s = \dfrac{1}{2a} (v² - u²)

s =  \dfrac{ {v}^{2} \: - \: {u}^{2} }{2a}

\boxed{\boxed{2as\:=\:{v}{^2}\:-\:{u}^{2}}}
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