Question

derive electric field due to uniformly charged thin spherical shell​

Answer 1

Explanation:

Derive the expression for electric field intensity due to a uniformly charged thin spherical shell. ... As there is no charge inside the spherical shell, Gaussian surface encloses no charge. That is q=0. Hence the field inside the spherical shell is always zero

Answer 2

Answer:

Consider a point P inside the shell at a distance r from the center.

A Gaussian sphere of radius r is constructed.

Applying Gauss law.

$E.4\pi {r}^{2} = \frac{Q}{ε_{o} }$

Since Gaussian surface encloses no charge,

So Q = 0.

The equation (5) becomes

E = 0 (r < R) ………….. (6)

The electric field due to the uniformly charged spherical shell is zero at all points inside the shell.

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