CBSE BOARD XII, asked by shan2863, 9 months ago

Derive electric field intensity due to a non conducting charged solid sphere.
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Answers

Answered by soniasanjeev399
2

Explanation:

The charge enclosed by such Gaussian surface is zero. Hence, electric field at each point of Gaussian surface is zero. This is true for all Gaussian surfaces having radii between 0 to R where R is inner radius of the shell. Therefore electric field inside a uniformly charged non- conducting spherical shell is zero

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