Question

derive equation 3rd of motion​

Answer 1

Answer:

HELLO GUYS HERE IS YOUR ANSWER

Step-by-step explanation:

Consider a body of mass “m” having initial velocity “u”. Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. This is the first equation of motion. ... This is the third equation of motion.

Answer 2

Answer:

Derivation of Third Equation of Motion

The third equation of motion is:

v2 = u2 + 2aS

Derivation of Third Equation of Motion by Algebraic Method

Derivation of Third Equation of Motion by Graphical Method

The total distance travelled, S = Area of trapezium OABC.

So, S= 1/2(SumofParallelSides)×Height

S=(OA+CB)×OC

Since, OA = u, CB = v, and OC = t

The above equation becomes

S= 1/2(u+v)×t

Now, since t = (v – u)/ a

The above equation can be written as:

S= 1/2(u+v)×(v-u)/a

Rearranging the equation, we get

S= 1/2(v+u)×(v-u)/a

S = (v2-u2)/2a

Third equation of motion is obtained by solving the above equation:

v2 = u2+2aS

Derivation of Third Equation of Motion by Calculus Method

It is known that,