derive equation for maximum work
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refer to the image for answer
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Explanation:
Here work done is calculated with the help of
Work = Pressure * change in volume
Work = -(-P – dP) – dV
Work = -(-PdV – dPdV)
For the expansion of the gas, the expansion will be taken into consideration, so integrate the over equation,
Integrate to o to wmax dw = integrate to v1 to v2 PdV
Ideal gas, P = nRT/V
Integrate o to wmax dw = integrate v1 to v2 nRT/V dt
On calculation, Wmax = -4.606 RT Log10 (V2/V1)
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