Derive Equation
v²-u²
= 2 as
Answers
Answered by
0
Answer:
it is as initial velocity -final Velocity
Explanation:
mark me as Brainliest
Answered by
0
Explanation:
We will use both of the equations of motion to reach the third equation of motion
S = ut + 1/2 at^2 and v = u + at, include the time variant t
There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.
To do this, we rearrange our first equation to get t = v - u / t
and use this to replace t wherever it appears in that second equation. So
S = ut + 1/2 at^2 becomes,
S = u ( v- u / a ) + 1/2 a ( v - u / a )^2
2aS = 2u ( v - u) + ( v - u ) ^2
2aS = 2uv - 2u^2 - v^2 - 2uv - u^2
2aS = v^2 - u^2
therefore, v^2 - u^2 = 2aS
Hope this will help you
Similar questions