Derive Eulers expansion of pi^2 /6
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Answered by
1
Answer:
basel problem
Step-by-step explanation:
10+10=20
Answered by
0
Answer:
Euler observed that the function
sin x
has roots at x = 0, ±π, ±2π, ±3π, . . .
Next, he observed that the infinite product
x
1 −
x
2
(π)
2
1 −
x
2
(2π)
2
1 −
x
2
(3π)
2
· · ·
also has roots at x = 0, ±π, ±2π, ±3π, . . .
Euler believed that these two functions are equivalent
By Maclaurin series on sin x, we find that the coefficient of the x
3
term = −1/6
On the other hand, for the infinite product, the coefficient of the x
3
term = −I/π2 = −
P∞
k=1 1/(k
2π
2
)
Thus, Euler concluded that I = π
2/6
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