Question

Derive expression for a time taken by a body to reach maximum height

Answer 1

If a body is thrown vertically upwards with initial velocity u to a height h then there will be retardation (a=-g). So we have equations of motion as:

v=u-gt ………(1)

h=ut - 1/2gt^2 …….(2)

v^2-u^2=-2gh…….(3)

At maximum height v=0 so

From (3) we get

-u^2=-2gh

h=u^2/2g

Answer 2

Answer:

hope u will understand