Question

derive expression for change in the value of g acceleration due to gravity due to change in height​

Answer 1

Answer:

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Explanation:

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Answer 2

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To calculate the value of g, we should put the values of G, M and R

Where G=universal gravitational constant, G=6.7×${10}^{ –11}$ Nm

${2kg}^{ −2}$mass of the earth, M=6×10 24

kg,

and radius of the earth, R=6.4×106m.

g= R 2GM

g= (6×${10}^{ 6}$ ) 2

6.67×${10 }^{−11}$

×6×10 24

=9.8m/s

Thus, the value of acceleration due to gravity of the earth, g=9.8m/s

Also we know Weight in nothing but the force exerted by the earth with a value of acceleration =9.8m/s

Now at the poles the value of acceleration due to gravity is higher as compared to the equator as the constant value of

g depends on the radius of the earth which decreases when we come down from poles to the equator.