derive expression for electric potential at a point on the axis of an electric dipole
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Answer:
Let P be an axial point at distance r from the center of the dipole. Electric potential at point P is given as
V=V
1
+V
2
V
1
and V
2
are the potentials at point P due to charges +q and –q respectively
V=
4πε
0
1
(
r−2a
q
+(
r+2a
−q
))
V=
4πε
0
1
(
(r
2
−4a
2
)
4a
)
V=
4πε
0
1
(
(r
2
−4a
2
)
2P
)
Hence, the electric potential is
4πε
0
1
(
(r
2
−4a
2
)
2P
)
Explanation:
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