derive expression for instantaneous velocity of projectile motion...??
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We know ,at any instant t
vx= u
vy= gt
v= (vx2 + vy2)1/2 = [u2 + (gt)2]1/2
Direction of v with the horizontal at any instant :
(angle) = tan-1 (vy/vx)= tan-1 (gt/u)
Time of flight (T):
It is the total time for which the projectile is in flight ( from O to B in the diagram above)
To find T we will find the time for vertical fall
From y= uyt + (1/2) gt2
When , y= h , t=T
h= 0 + (1/2) gt2
T= (2h/g)1/2
Range (R) :
It is the horizontal distance covered during the time of flight T.
From x= ut
When t=T , x=R
R=uT
R=u(2h/g)1/2
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