Question

Derive expression for lateral displacement also write down laws of reflection and reflection?​

Answer 1

Answer:

drive expression for lateral displacement

Answer 2

Answer:

The slab's thickness affects how much space is displaced laterally. The lateral displacement will be larger the thicker the slab. The lateral displacement will be greater the more acute the incidence angle.

Explanation:

Step 1: Imagine a glass slab with a thickness of t and a refractive index of n that is preserved in an airy environment. The refractions in the glass slab take place at positions B and C along the light's path, which is ABCD. At the two places B and C, respectively, the angles of incidence I and refraction r are determined in relation to the normals N1 and N2. The lateral displacement L is the angle CE measured perpendicularly between the light's path and its undeviated path at point C. The right-angled triangle around BCE.

Step 2: Refraction in glass slab

$\sin \left(\mathrm{i}-\ulcorner)=\frac{L}{B C} ; B C=\frac{L}{\sin (i-r)}\right.$

In the right angle triangle $\triangle \mathrm{BCF}$

$\cos (\mathrm{r})=\frac{t}{B C} ; \mathrm{BC}=\frac{t}{\cos (r)} \cdots \cdots$

Equating equations (1) and (2)

$\frac{L}{\sin (i-r)}=\frac{t}{\cos (r)}$

Step 3: After rearranging,

$\mathrm{L}=\mathrm{t}\left(\frac{\sin (i-r)}{\cos (r)}\right)$

The slab's thickness affects how much space is displaced laterally. The lateral displacement will be larger the thicker the slab. The lateral displacement will be greater the more acute the incidence angle.

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