derive expression for orbital magnetic moment of an electron revolving in circular orbit in an atom
Answers
Answered by
0
Answer:
Consider an electron revolving around a nucleus in an atom. Since the electron is a negatively charged particle, so atom will act as a current-carrying loop and its magnetic dipole moment is given by
M=lA
Where l =current and A =area of cross-section
if r is the radius of orbit then
M=(te)(πr2)
=v2πreπr2=2evr
Sice mvr = angular momentum (L)
So, M=(2me2)L (in vector form), since magnetic dipole moment of the electron and angular momentum are in opposite direction.
Similar questions