Derive expression for pressure at a depth h in a liquid
Answers
Answered by
3
hiiii
Let us consider a container which contains a liquid of density d.consider a cylindrical column of height h from the surface of liquid of cross section area A.the volume of liquid columnV=Ax hmass = density x volumem= Axhxdweight w= mxgw=mg= Axhxdxgthere are three forces acting on water column. 1. weight, vertically down.2. force on top surface due to atmospheric pressure ( P°A), acting vertically Down.3. Force on bottom surface if column due to static pressure of liquid ( PA), acting vertically upfrom Newton's lawPA= P° A +wPA = P° A + hdgAP= P° + hdgnote : P° read it as p not.
Let us consider a container which contains a liquid of density d.consider a cylindrical column of height h from the surface of liquid of cross section area A.the volume of liquid columnV=Ax hmass = density x volumem= Axhxdweight w= mxgw=mg= Axhxdxgthere are three forces acting on water column. 1. weight, vertically down.2. force on top surface due to atmospheric pressure ( P°A), acting vertically Down.3. Force on bottom surface if column due to static pressure of liquid ( PA), acting vertically upfrom Newton's lawPA= P° A +wPA = P° A + hdgAP= P° + hdgnote : P° read it as p not.
Answered by
9
Let us consider a container which contains a liquid of density d.
consider a cylindrical column of height h from the surface of liquid of cross section area A.
the volume of liquid column
V=Ax h
mass = density x volume
m= Axhxd
weight w= mxg
w=mg
= Axhxdxg
there are three forces acting on water column.
1. weight, vertically down.
2. force on top surface due to atmospheric pressure ( P°A), acting vertically Down.
3. Force on bottom surface if column due to static pressure of liquid ( PA), acting vertically up
from Newton's law
PA= P° A +w
PA = P° A + hdgA
P= P° + hdg
note : P° read it as p not.
consider a cylindrical column of height h from the surface of liquid of cross section area A.
the volume of liquid column
V=Ax h
mass = density x volume
m= Axhxd
weight w= mxg
w=mg
= Axhxdxg
there are three forces acting on water column.
1. weight, vertically down.
2. force on top surface due to atmospheric pressure ( P°A), acting vertically Down.
3. Force on bottom surface if column due to static pressure of liquid ( PA), acting vertically up
from Newton's law
PA= P° A +w
PA = P° A + hdgA
P= P° + hdg
note : P° read it as p not.
Similar questions