derive expression for total time of flight
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to Find the time of flight determine the time the projectile takes to reach maximum height.the time of flight is just double the maximum height time.
v equals to voy + ayt
at maximum height vy equals to zero
the time to reach maximum height is t1/2 equals to - voy/ ay
t equals to 2t1/2 equals to -2voy/ay
voy equals to vo sin(q) and ay equals to -g
t equals to 2vo sin (q)/g
g equals to 9.8m/s2
v equals to voy + ayt
at maximum height vy equals to zero
the time to reach maximum height is t1/2 equals to - voy/ ay
t equals to 2t1/2 equals to -2voy/ay
voy equals to vo sin(q) and ay equals to -g
t equals to 2vo sin (q)/g
g equals to 9.8m/s2
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