Question

Derive expression of period simple pendulum using dimension?

Answer 1

Answer:

Or, T = √[M0 L1 T0] × [M0 L1 T-2]-1 = √[T2] = [M0 L0 T1]. Therefore, the time period is dimensionally represented as [M0 L0 T1].

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Answer 2

Explanation:

Dimensional Formula of Time Period

The dimensional formula of Time Period is given by,

[M0 L0 T1]

Where,

M = Mass

L = Length

T = Time

Derivation

Time Period (T) = 2× π × √(L/g) . . . . . (1)

Where, L = length of string and g = Acceleration due to gravity

The dimensional formula of length = [M0 L1 T0] . . . . (2)

And, the dimensional formula of accleration due to gravity = [M0 L1 T-2] . . . . (3)

On substituting equation (2) and (3) in equation (1) we get,

Time Period (T) = 2× π × √(L/g)

Or, T = √[M0 L1 T0] × [M0 L1 T-2]-1 = √[T2] = [M0 L0 T1].

Therefore, the time period is dimensionally represented as [M0 L0 T1].