Question

Derive expressions for velocity after a time 't'
horizotal displacement, vertical displacement
after a time 't' and position vector too​

Answer 1

Answer:

idk

thnx for points

Explanation:

lol xd

Answer 2

Answer:

Describing Projectiles With Numbers: (Horizontal and Vertical Displacement)

What is a Projectile?

Motion Characteristics of a Projectile

Horizontal and Vertical Velocity

Horizontal and Vertical Displacement

Initial Velocity Components

Horizontally Launched Projectile Problems

Non-Horizontally Launched Projectile Problems

The previous diagrams, tables, and discussion pertain to how the horizontal and vertical components of the velocity vector change with time during the course of projectile's trajectory. Now we will investigate the manner in which the horizontal and vertical components of a projectile's displacement vary with time. As has already been discussed, the vertical displacement (denoted by the symbol y in the discussion below) of a projectile is dependent only upon the acceleration of gravity and not dependent upon the horizontal velocity. Thus, the vertical displacement (y) of a projectile can be predicted using the same equation used to find the displacement of a free-falling object undergoing one-dimensional motion. This equation was discussed in Unit 1 of The Physics Classroom. The equation can be written as follows.

y = 0.5 • g • t2

(equation for vertical displacement for a horizontally launched projectile)

where g is -9.8 m/s/s and t is the time in seconds. The above equation pertains to a projectile with no initial vertical velocity and as such predicts the vertical distance that a projectile falls if dropped from rest. It was also discussed earlier, that the force of gravity does not influence the horizontal motion of a projectile. The horizontal displacement of a projectile is only influenced by the speed at which it moves horizontally (vix) and the amount of time (t) that it has been moving horizontally. Thus, if the horizontal displacement (x) of a projectile were represented by an equation, then that equation would be written as

x = vix • t

The diagram below shows the trajectory of a projectile (in red), the path of a projectile released from rest with no horizontal velocity (in blue) and the path of the same object when gravity is turned off (in green). The position of the object at 1-second intervals is shown. In this example, the initial horizontal velocity is 20 m/s and there is no initial vertical velocity (i.e., a case of a horizontally launched projectile).

As can be seen in the diagram above, the vertical distance fallen from rest during each consecutive second is increasing (i.e., there is a vertical acceleration). It can also be seen that the vertical displacement follows the equation above (y = 0.5 • g • t2). Furthermore, since there is no horizontal acceleration, the horizontal distance traveled by the projectile each second is a constant value - the projectile travels a horizontal distance of 20 meters each second. This is consistent with the initial horizontal velocity of 20 m/s. Thus, the horizontal displacement is 20 m at 1 second, 40 meters at 2 seconds, 60 meters at 3 seconds, etc. This information is summarized in the table below.

Time

Horizontal

Displacement

Vertical

Displacement

0 s

0 m

0 m

1 s

20 m

-4.9 m

2 s

40 m

-19.6 m

3 s

60 m

-44.1 m

4 s

80m

-78.4 m

5 s

100 m

-122.5 m