Derive F=ma
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Class 9
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Acoording to newtons 2nd law , Force acting on a body is directly proportional the rate of change in momentum.
F = force acting on a body
Change in momentum
= final momentum - initial momentum
= mv - mu
Rate of change in momentum =( mv - mu ) / t
Force is directly proportion to rate of change in momentum
F = k( mv - mu ) / t =k m { ( v - u ) / t } = km × a = kma
( since v - u / t = a )
where k = constant of proportionality
Thus F = kma ----(i)
now take m = 1 kg and a = 1 m/s^-2 and F = 1 N in ( i ) we get
1 = k × 1 × 1 => k= 1 , putting in ( i ) we get
F = ma
F = force acting on a body
Change in momentum
= final momentum - initial momentum
= mv - mu
Rate of change in momentum =( mv - mu ) / t
Force is directly proportion to rate of change in momentum
F = k( mv - mu ) / t =k m { ( v - u ) / t } = km × a = kma
( since v - u / t = a )
where k = constant of proportionality
Thus F = kma ----(i)
now take m = 1 kg and a = 1 m/s^-2 and F = 1 N in ( i ) we get
1 = k × 1 × 1 => k= 1 , putting in ( i ) we get
F = ma
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63
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