derive f=ma ,wher f is force acting on the body of mass m and a accelaration of the body
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Answered by
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Force is directoly proportional to change in momemtum
we remove the proportionality sign and put k whose value is 1
F=(mv-mu)t
F=m(v-u)/t
F=ma (a=(v-u)/t)
Hope u got that
we remove the proportionality sign and put k whose value is 1
F=(mv-mu)t
F=m(v-u)/t
F=ma (a=(v-u)/t)
Hope u got that
Answered by
2
HEYA ..MATEY ..^_^❤✌️
THERE'S YOUR ANSWER ....
WE KNOW THAT , FORCE , IS DIRECTLY PROPORTIONAL TO THE CHANGE IN VELOCITY AND INVERSELY PROPORTIONAL TO THE TOTAL TIME TAKEN ..
SO , THE DERIVATION OF THE FORMULA ..
F = ma ,
WOULD BE AS FOLLOWS ......
F is directly proportional to (mv - mu )/t
TO REMOVE THE PROPORTION SYMBOL, WE NEED TO MULTIPLY ,THE CONSTANT OF PROPORTIONALITY 'k' WITH ,( mv - mu) / t
F =k( mv - mu ) / t
HERE , k = 1 unit
=> F = m ( v-u ) / t
=> F = ma , ( a = v - u / t )
HENCE, DERIVED ,
F = ma
THERE'S YOUR ANSWER ....
WE KNOW THAT , FORCE , IS DIRECTLY PROPORTIONAL TO THE CHANGE IN VELOCITY AND INVERSELY PROPORTIONAL TO THE TOTAL TIME TAKEN ..
SO , THE DERIVATION OF THE FORMULA ..
F = ma ,
WOULD BE AS FOLLOWS ......
F is directly proportional to (mv - mu )/t
TO REMOVE THE PROPORTION SYMBOL, WE NEED TO MULTIPLY ,THE CONSTANT OF PROPORTIONALITY 'k' WITH ,( mv - mu) / t
F =k( mv - mu ) / t
HERE , k = 1 unit
=> F = m ( v-u ) / t
=> F = ma , ( a = v - u / t )
HENCE, DERIVED ,
F = ma
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