Question

derive first equation of motion from velocity time graph of an object​

Answer 1

Answer:

velocity time graph -v=u+at

consider a velocity time graph for a body moving with uniform acceleration'a' . The intial velocity is 'v' at A and final velocity is 'v' at b in time 't'.

perpendicular lines BC and BE are drawn from point B to time and velocity axes, so that intial velocity is OA and final velocity is BC and time interval is OC.

we will observe:-

BC=DD+DC=DD+OA

substituting BC=V and OA=U

we get v=BD+U

or BD=V-U

Acceleration = change in velocity

time

Acceleration =BD = BD or a=v-u

AD OC t

so we concluded

V-u=at or V=U+at