Physics, asked by utakarsh, 1 year ago

Derive first, second and third equation of motion

Answers

Answered by Anonymous
0
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Answered by Harshitasood
2
first equation of motion
a= v-u/t
at= v-u
u+at=v
second equation of motion
s=1/2(v+u)×t
from 1
s=1/2(u+u+at)×t
s= 1/2×2ut×1/2at^2
s= ut×1/2at^2
3 equation of motion
from 2
s= 1/2(v+u)×t
from 1
a=v-u/t
t= v-u/a
s= 1/2 (v+u)(v-u)/a
2as= v^2-u^2

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