Question

Derive following expression for uniformly accelerated motion S= u t +1/2 at^2

Answer 1

Answer:

S=ut +1/2 at ^2

Explanation:

Average velocity = Final velocity +initial velocity /2

V^av= v+u/2

Distance =v^av×t

S= [v+u/2]×t (from equation 1st of motion)

S= [ at +u+u/2]×t

S=[at+2u /2]×t

S=[at/2+2u/2]×t

S=ut+1/2 at^2

HOPE IT WILL HELP U!!!

Answer 2

Answer:

S= ut +1/2 at^2

Explanation:

average velocity =v +u /2

distance = Av. velocity ×Time

s= (v + u /2)×T

v= u + at (from 1st equation of motion )

s =( u + at + u /2 )×t

s =(2u /2 + at /2)×t

s = ut +1/2at ^2

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